# Predict the Products of Electrolysis in Each of the Following: A Dilute Solution of H2so4 With Platinum Electrodes - Chemistry

Predict the products of electrolysis in the following:

A dilute solution of H2SO4 with platinum electrodes

#### Solution

H2SO4 ionizes in aqueous solutions to give H+ and SO_4^(2-) ions.

H_2SO_(4(aq)) -> 2H_((aq))^+ + SO_(4(aq))^(2-)

On electrolysis, either of H+ ions or H2O molecules can get reduced at the cathode. But the reduction potential of H+ ions is higher than that of H2O molecules.

2H_((aq))^+ + 2e^(-) -> H_(2(g)); E^@ = 0.0 V

2H_2O_((aq)) + 2e^(-) -> H_(2(g)) + 2OH_((aq))^(-) ; E^@ = -0.83 V

Hence, at the cathode, H+ ions are reduced to liberate H2 gas.

On the other hand, at the anode, either of SO_4^(2-)ions or H2O molecules can get oxidized. But the oxidation of SO_4^(2-) involves breaking of more bonds than that of H2O molecules. Hence, SO_4^(2-) ions have a lower oxidation potential than H2O. Thus, H2O is oxidized at the anode to liberate O2 molecules

Concept: Redox Reactions in Terms of Electron Transfer Reactions - Competitive Electron Transfer Reactions
Is there an error in this question or solution?

#### APPEARS IN

NCERT Class 11 Chemistry Textbook
Chapter 8 Redox Reactions
Q 27.3 | Page 275