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Pratham travels 10 metres in North direction, he turns right and travels 20 metres. Again, he turns towards right and travels 25 metres. Then, he turns towards left and travels 15 metres. In which direction and how far is Pratham from his original position?

#### Options

35 metres, East

38.07 metres, South-East

25.08 metres, West

25 metres, North-East

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#### Solution

38.07 metres, South-East

**Explanation:**

A = starting point of Pratham

C = end point of pratham

Distance between AC = `sqrt ("AB"^2 + "BC"^2)`

`=sqrt((15)^2 + (35)^2)`

`= sqrt(225+1225) = sqrt 1450` = 38.07 m

Therefore pratham is 38.07 m far from his original position and point C, which is end point is south- east from hos starting point A.

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