Department of Pre-University Education, KarnatakaPUC Karnataka Science Class 12
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# P the Particle P Shown in Figure Has a Mass of 10 Mg and a Charge of −0⋅01 µC. Each Plate Has a Surface Area 100 Cm2 on One Side. What Potential Difference V Should Be Applied to the Combination - Physics

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ConceptPotential Due to a Point Charge

#### Question

The particle P shown in figure has a mass of 10 mg and a charge of −0⋅01 µC. Each plate has a surface area 100 cm2 on one side. What potential difference V should be applied to the combination to hold the particle P in equilibrium?

#### Solution

The particle is balanced when the electrical force on it is balanced by its weight.

Thus,

mg = qE

mg = q xx V^'/d.............(1)

Here,

d = Separation between the plates of the capacitor

V' = Potential difference across the capacitor containing the particle

We know that the capacitance of a capacitor is given by

C = (∈_0A)/d

⇒ d = (∈_0A)/c

Thus, eq. (1) becomes

mg = q xx V^' xx C/(∈_0A)

⇒ V^' = (mg∈_0A)/(q xx c)

⇒ V^' = (10^-6 xx 9.8 xx (8.85 xx 10^-12) xx (100 xx 10^-4))/((0.01 xx 10^-6) xx (0.04 xx 10^-6)

⇒ V^' = 21.68  "mV"

Since the values of both the capacitors are the same,

V = 2V = 2 xx 21.86 ≈ 43  "mV"

Is there an error in this question or solution?

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Solution P the Particle P Shown in Figure Has a Mass of 10 Mg and a Charge of −0⋅01 µC. Each Plate Has a Surface Area 100 Cm2 on One Side. What Potential Difference V Should Be Applied to the Combination Concept: Potential Due to a Point Charge.
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