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# Solution - Drunkard Walking in a Narrow Lane Takes 5 Steps Forward and 3 Steps Backward, Followed Again by 5 Steps Forward and 3 Steps Backward, and So On. Each Step is 1 M Long and Requires 1 S. Plot The X-tgraph of His Motion. Determine Graphically and Otherwise How Long the Drunkard Takes to Fall in a Pit 13 M Away from the Start - Position, Path Length and Displacement

ConceptPosition, Path Length and Displacement

#### Question

A drunkard walking in a narrow lane takes 5 steps forward and 3 steps backward, followed again by 5 steps forward and 3 steps backward, and so on. Each step is 1 m long and requires 1 s. Plot the x-tgraph of his motion. Determine graphically and otherwise how long the drunkard takes to fall in a pit 13 m away from the start.

#### Solution

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#### APPEARS IN

NCERT Physics Textbook for Class 11 Part 1
Chapter 3: Motion in a Straight Line
Q: 4 | Page no. 56

#### Reference Material

Solution for question: Drunkard Walking in a Narrow Lane Takes 5 Steps Forward and 3 Steps Backward, Followed Again by 5 Steps Forward and 3 Steps Backward, and So On. Each Step is 1 M Long and Requires 1 S. Plot The X-tgraph of His Motion. Determine Graphically and Otherwise How Long the Drunkard Takes to Fall in a Pit 13 M Away from the Start concept: Position, Path Length and Displacement. For the courses CBSE (Arts), CBSE (Commerce), CBSE (Science)
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