Point P is at a distance of 6 cm from line AB. Draw a circle of radius 4 cm passing through point P so that line AB is the tangent to the circle
Solution
Analysis: As shown in the figure, A circle of radius 4 cm has center O.
Perpendicular distance of P from line AB = 6 cm.
∴ PY = 6 cm and ∠PYA = 90° ......(i)
seg OX is a perpendicular from point O to seg PY at point X.
Line AB is a tangent to the circle at point Z.
∴ OZ is radius of the circle.
In ▢XOZY,
∠X = 90° ......[∵ OX ⊥ PY]
∠Y = 90° ......[From (i)]
∠Z = 90° ......[Tangent theorem]
∴ ∠O = 90° ......[Remaning angle of ▢XOZY]
∴ ▢XOZY is a rectangle.
. ∴ seg ZY = seg OX and seg XO = seg YZ ......[Opposite sides of a rectangle]
But OZ = 4 cm ......…[Radius of the circle]
∴ XY = 4 cm
Steps of construction:
- Draw line AB.
- From any point Q on line AB, draw a, perpendicular PQ of 6 cm.
- Draw point X on seg PQ such that seg XQ = 4 cm.
- Draw ray XY interior of the circle such that ∠QXY = 90°
- Taking distance of 4 cm in compass, draw an arc with centre P on ray XY and name the point of intersection as O.
- With centre O, draw a circle of radius 4 cm. Which is the required circle.