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Plot a graph showing variation of de Broglie wavelength λ versus `1/sqrtV` , where *V* is accelerating potential for two particles A and B, carrying the same charge but different masses *m*_{1}, *m*_{2} (*m*_{1} > *m*_{2}). Which one of the two represents a particle of smaller mass and why?

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#### Solution

Given: Charge (*q*) is the same but masses of both the particles are different (*m*_{1 }> *m*_{2}).

The de Brogile wavelength given by

`lambda = h/sqrt(2mqV)`

The slope of the graph λ versus `1/sqrtV `is `h/sqrt(2mq)`

The slope of the smaller mass is larger; therefore, plot A in the above graph is for mass *m*_{2}

Concept: de-Broglie Relation

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