Question

Plot a graph showing variation of de Broglie wavelength λ versus `1/sqrtV` , where V is accelerating potential for two particles A and B, carrying the same charge but different masses m₁, m₂ (m₁ > m₂). Which one of the two represents a particle of smaller mass and why?

Answer 1

Given: Charge (q) is the same but masses of both the particles are different (m₁ > m₂).

The de Brogile wavelength given by

`lambda = h/sqrt(2mqV)`

The slope of the graph λ versus `1/sqrtV `is `h/sqrt(2mq)`

The slope of the smaller mass is larger; therefore, plot A in the above graph is for mass m₂