HSC Science (Electronics) 12th Board ExamMaharashtra State Board
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A wheel of moment of inertia 1 kgm^2 is rotating at a speed of 40 rad/s. Due to friction on the axis, the wheel comes to rest in 10 minutes. - HSC Science (Electronics) 12th Board Exam - Physics

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Question

A wheel of moment of inertia 1 Kgm 2 is rotating at a speed of 40 rad/s. Due to friction on the axis, the wheel comes to rest in 10 minutes. Calculate the angular momentum of the wheel, two minutes before it comes to rest.

Solution

`omega =omega_0+alphat`

`0=40+alpha600`

`therefore alpha=-0.06666 rad/s^2`

`thereforeomega=40-0.06666 xx 480 `

`therefore omega=8 "rad"/s`

 

 

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APPEARS IN

 2012-2013 (March) (with solutions)
Question 2.8 | 2.00 marks
Solution A wheel of moment of inertia 1 kgm^2 is rotating at a speed of 40 rad/s. Due to friction on the axis, the wheel comes to rest in 10 minutes. Concept: Physical Significance of M.I (Moment of Inertia).
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