Question
A wheel of moment of inertia 1 Kgm 2 is rotating at a speed of 40 rad/s. Due to friction on the axis, the wheel comes to rest in 10 minutes. Calculate the angular momentum of the wheel, two minutes before it comes to rest.
Solution
`omega =omega_0+alphat`
`0=40+alpha600`
`therefore alpha=-0.06666 rad/s^2`
`thereforeomega=40-0.06666 xx 480 `
`therefore omega=8 "rad"/s`
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APPEARS IN
Solution A wheel of moment of inertia 1 kgm^2 is rotating at a speed of 40 rad/s. Due to friction on the axis, the wheel comes to rest in 10 minutes. Concept: Physical Significance of M.I (Moment of Inertia).
