#### Question

A uniform solid sphere has radius 0.2 m and density 8 x 10^{3} kg/m^{3}. Find the moment of

inertia about the tangent to its surface. (π = 3.142)

#### Solution

Solution:

Given: R = 0.2m, ρ= 8000 Kg/m^{3}

To find: Moment of inertia (I)

Formulae:

i. `I_0=I_c+MR^2`

`I_0=2/5 MR^2 + MR^2`

`I_0=7/5 MR^2`

ii. Mass (M) = volume x density

from formula 2

`M=Vrho=(4/3piR^3)rho`

from formula 1

`I=7/5(4/3piR^3rho)R^2`

`=28/15 piR^5rho`

`=28/15xx3.14xx(2xx10^-1)^5xx8000`

`I=15.02` kgm^{2}

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#### APPEARS IN

Solution A uniform solid sphere has radius 0.2 m and density 8 x 10^3 kg/m^3. Find the moment of inertia about the tangent to its surface. Concept: Physical Significance of M.I (Moment of Inertia).