HSC Science (Electronics) 12th Board ExamMaharashtra State Board
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# A uniform solid sphere has radius 0.2 m and density 8 x 10^3 kg/m^3. Find the moment of inertia about the tangent to its surface. - HSC Science (Electronics) 12th Board Exam - Physics

ConceptPhysical Significance of M.I (Moment of Inertia)

#### Question

A uniform solid sphere has radius 0.2 m and density 8 x 103 kg/m3. Find the moment of
inertia about the tangent to its surface. (π = 3.142)

#### Solution

Solution:
Given: R = 0.2m, ρ= 8000 Kg/m3
To find: Moment of inertia (I)

Formulae:

i. I_0=I_c+MR^2

I_0=2/5 MR^2 + MR^2

I_0=7/5 MR^2

ii. Mass (M) = volume x density

from formula 2

M=Vrho=(4/3piR^3)rho

from formula 1

I=7/5(4/3piR^3rho)R^2

=28/15 piR^5rho

=28/15xx3.14xx(2xx10^-1)^5xx8000

I=15.02 kgm2

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#### APPEARS IN

2016-2017 (July) (with solutions)
Question 2.4 | 3.00 marks
Solution A uniform solid sphere has radius 0.2 m and density 8 x 10^3 kg/m^3. Find the moment of inertia about the tangent to its surface. Concept: Physical Significance of M.I (Moment of Inertia).
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