HSC Science (General) 12th Board ExamMaharashtra State Board
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A Solid Cylinder of Uniform Density of Radius 2 cm Has Mass of 50g. If Its Length is 12 cm, Calculate Its Moment of Inertia About an Axis Passing Through Its Centre and Perpendicular to Its Length. - HSC Science (General) 12th Board Exam - Physics

ConceptPhysical Significance of M.I (Moment of Inertia)

Question

A solid cylinder of uniform density of radius 2 cm has mass of 50 g. If its length is 12 cm, calculate its moment of inertia about an axis passing through its centre and perpendicular to its length.

Solution

m=50gm , L=12cm

R=2cm

I=((ml^2)/12+(mR^2)/4)=m(l^2/12+R^2/4)

:.I=50[(12xx12)/12+4/4]

= 50 x 13

=650 dyne-cm2

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APPEARS IN

2013-2014 (March) (with solutions)
Question 1.8 | 2.00 marks
Solution A Solid Cylinder of Uniform Density of Radius 2 cm Has Mass of 50g. If Its Length is 12 cm, Calculate Its Moment of Inertia About an Axis Passing Through Its Centre and Perpendicular to Its Length. Concept: Physical Significance of M.I (Moment of Inertia).
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