#### Question

A copper metal cube has each side of length 1 m. The bottom edge of the cube is fixed and tangential force 4.2x10^{8} N is applied to a top surface. Calculate the lateral displacement of the top surface if modulus of rigidity of copper is 14x10^{10} N/m^{2}.

#### Solution

Given

η=14x10^{10} N/m

F=4.2x10^{8} N

A=1x1=1m^{2}

`eta=(Fh)/(Ax)`

`x=(Fh)/(Aeta)`

`=(4.2xx10^8xx1m)/(1xx14xx10^10)`

`=(4.2xx10^8)/(14xx10^10)`

=0.3x10^{-2}m=3mm

Is there an error in this question or solution?

#### APPEARS IN

Solution A copper metal cube has each side of length 1 m. The bottom edge of the cube is fixed and tangential force 4.2x10^8 N is applied to a top surface. Concept: Periodic and Oscillatory Motions.