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Solution - Calculate the Mass Percent of Different Elements Present in Sodium Sulphate (Na2so4). - CBSE (Science) Class 11 - Chemistry

Question

Calculate the mass percent of different elements present in sodium sulphate (Na2SO4).

Solution

The molecular formula of sodium sulphate is Na2SO4

Molar mass of Na2SO4 = [(2 × 23.0) + (32.066) + 4 (16.00)] = 142.066 g

`"Mass percent of an element "="Mass of the element in the compound"/"Molar mass of the compound"xx100`

∴ Mass percent of sodium :-

`=(46.0g)/(142.066g)xx100`

 = 32.379

= 32.4%

Mass percent of sulphur :-

`=(32.066g)/(142.066g)xx100`

= 22.57

= 22.6%

Mass percent of oxygen :-

`=(64.0g)/(142.066g)xx100`

= 45.049

= 45.05%

  Is there an error in this question or solution?

APPEARS IN

 NCERT Chemistry Textbook for Class 11 Part 1 (with solutions)
Chapter 1: Some Basic Concepts of Chemistry
Q: 1.2 | Page no. 22

Reference Material

Solution for question: Calculate the Mass Percent of Different Elements Present in Sodium Sulphate (Na2so4). concept: Percentage Composition. For the course CBSE (Science)
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