#### Question

The joint equation of the pair of lines passing through (2,3) and parallel to the coordinate axes is

- xy -3x - 2y + 6 = 0
- xy +3x + 2y + 6 = 0
- xy = 0
- xy - 3x - 2y - 6 = 0

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#### Solution

(a)

Equation of the coordinate axes are x = 0 and y = 0.

The equations of the lines passing through (2, 3) and parallel to coordinate axes are,

x = 2 and y = 3.

i.e. x - 2 = 0 and y - 3 = 0

The joint equation is given as

(x-2)(y-3)=0

xy-3x-2y+6=0

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