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# P a Particle is Projected with a Speed U at an Angle θ with the Horizontal. Consider a Small Part of Its Path Near the Highest Position and Take It Approximately to Be a Circular Arc. - Physics

ConceptCircular Motion

#### Question

A particle is projected with a speed u at an angle θ with the horizontal. Consider a small part of its path near the highest position and take it approximately to be a circular arc. What is the radius of this circular circle? This radius is called the radius of curvature of the curve at the point.

#### Solution

At the highest point, the vertical component of velocity is zero.
So, at the highest point, we have:
velocity = v = ucosθ
Centripetal force on the particle = $\frac{m v^2}{r}$

$\Rightarrow \frac{m v^2}{r} = \frac{m u^2 \cos^2 \theta}{r}$

At the highest point, we  have :

$mg = \frac{m v^2}{r}$

Here, r is the radius of curvature of the curve at the point.

$\Rightarrow r = \frac{u^2 \cos^2 \theta}{g}$
Is there an error in this question or solution?

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Solution P a Particle is Projected with a Speed U at an Angle θ with the Horizontal. Consider a Small Part of Its Path Near the Highest Position and Take It Approximately to Be a Circular Arc. Concept: Circular Motion.
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