Give the formula and describe the structure of a noble gas species which is isostructural with
ICI4–: In ICI4–, central atom I has seven valence electrons and one due to negative charge. Four out of these 8 electrons are utilized in forming four single bonds with four Cl atoms. Four remaining electrons constitutes the two lone pairs. It is arranged in square planar structure. ICI4– has 36 valence electrons. A noble gas species having 36 valence electrons is XeF4 (8 + 4 x 7 = 36). XeF4 is also square planar.
XeF4 is isoelectronic with `ICI_4^(-)` and has square planar geometry.