Out of C6H5CH2Cl and C6H5CHClC6H5, which is more easily hydrolysed by aqueous KOH?
Hydrolysis by aqueous KOH proceeds through the formation of carbocation. If carbocation is stable, then the compound is easily hydrolyzed by aqueous KOH. Now, `C_6H_5CH_2Cl` forms 1°-carbocation, while C6H5CHClC6H5 forms 2°-carbocation, which is more stable than 1°-carbocation. Hence, `C_6H_5CHClC_6H_5` is hydrolyzed more easily than `C_6H_5CH_2Cl` by aqueous KOH.
Video Tutorials For All Subjects
- Chemical Reactions of Haloalkanes and Haloarenes - Reactions of Haloalkanes - Nucleophilic Substitution Reactions