#### Questions

Order and degree of the differential equation `[1+(dy/dx)^3]^(7/3)=7(d^2y)/(dx^2)` are respectively

(A) 2, 3

(B) 3, 2

(C) 7, 2

(D) 3, 7

The order and degree of the differential equation `[1+(dy/dx)^3]^(7/3)=7(d^2y)/(dx^2)` are respectively

(A) 2, 3

(B) 3, 2

(C) 2, 2

(D) 3, 3

#### Solution

`[1+(dy/dx)^3]^(7/3)=7(d^2y)/(dx^2)`

Cubing on both sides, we get

`[1+(dy/dx)^3]^(7)=7((d^2y)/(dx^2))^3`

By definition of degree and order Degree: 3 ; Order: 2

Is there an error in this question or solution?

Solution for question: Order and Degree of the Differential Equation concept: Order and Degree of a Differential Equation. For the courses HSC Science (Electronics), HSC Science (Computer Science), HSC Arts, HSC Science (General)