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Simplify 2/(Sqrt5 + Sqrt3) + 1/(Sqrt3 + Sqrt2) + 3/(Sqrt5 + Sqrt2) - CBSE Class 9 - Mathematics

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Question

Simplify

`2/(sqrt5 + sqrt3) + 1/(sqrt3 + sqrt2) + 3/(sqrt5 + sqrt2)`

Solution

We know that rationalization factor for `sqrt5 + sqrt3`, `sqrt3 + sqrt2` and `sqrt5 + sqrt2` are `sqrt5 - sqrt3`, `sqrt3 - sqrt2` and `sqrt5 - sqrt2` respectively. We will multiply numerator and denominator of the given expression `2/(sqrt5 + sqrt3)`, `1/(sqrt3 + sqrt2)` and `3/(sqrt5 + sqrt2)` by `2 - sqrt3`, `sqrt5 + sqrt3` and `2 + sqrt5`respectively to get

`2/(sqrt5 + sqrt3) xx (sqrt5 - sqrt3)/(sqrt5 - sqrt3) + 1/(sqrt3 + sqrt2) xx (sqrt3 - sqrt2)/(sqrt3 - sqrt2) - 3/(sqrt5 + sqrt2) xx (sqrt5  - sqrt2)/(sqrt5 - sqrt2) = (2sqrt5 - 2sqrt3)/(5 - 3) + (sqrt3 - sqrt2)/(3 - 2) - (3sqrt5 - 3sqrt2)/(5 - 2)`

` = (2sqrt5 - 2sqrt3)/2 + (sqrt3 - sqrt2)/1 - (3sqrt5 - 3sqrt2)/3`

`= sqrt5 - sqrt3 + sqrt3 - sqrt2 - sqrt5 + sqrt2`

= 0

Hence the given expression is simplified to 0

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Solution Simplify 2/(Sqrt5 + Sqrt3) + 1/(Sqrt3 + Sqrt2) + 3/(Sqrt5 + Sqrt2) Concept: Operations on Real Numbers.
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