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# Find the Value to Three Places of Decimals of the Following. It is Given that Sqrt2 = 1.414, Sqrt3 = 1.732, Sqrt5 = 2.236 and Sqrt10 = 3.162 - CBSE Class 9 - Mathematics

ConceptOperations on Real Numbers

#### Question

Find the value to three places of decimals of the following. It is given that

sqrt2 = 1.414, sqrt3 = 1.732, sqrt5 = 2.236 and sqrt10 = 3.162

(sqrt2 - 1)/sqrt5

#### Solution

We know that rationalization factor of the denominator is sqrt5. We will multiply numerator and denominator of the given expression (sqrt2 - 1)/sqrt5by sqrt5 to get

(sqrt2 - 1)/sqrt5 xx sqrt5/sqrt5 = (sqrt2 xx sqrt5 - sqrt5)/(sqrt5 xx sqrt5)

= (sqrt10 - sqrt5)/5

Putting the value of sqrt10and sqrt5 we get

(sqrt10 - sqrt5)/5 = (3.162 - 2.236)/5

= 0.926/5

= 0.1852

The value of expression 0.1852 can be round off tp three decimal places as 0.185.

given expression is simplified to 0.185

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Solution Find the Value to Three Places of Decimals of the Following. It is Given that Sqrt2 = 1.414, Sqrt3 = 1.732, Sqrt5 = 2.236 and Sqrt10 = 3.162 Concept: Operations on Real Numbers.
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