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Find the Value to Three Places of Decimals of the Following. It is Given that Sqrt2 = 1.414, Sqrt3 = 1.732, Sqrt5 = 2.236 and Sqrt10 = 3.162 - CBSE Class 9 - Mathematics

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Question

Find the value to three places of decimals of the following. It is given that

`sqrt2 = 1.414`, `sqrt3 = 1.732`, `sqrt5 = 2.236` and `sqrt10 = 3.162`

`(sqrt2 - 1)/sqrt5`

Solution

We know that rationalization factor of the denominator is `sqrt5`. We will multiply numerator and denominator of the given expression `(sqrt2 - 1)/sqrt5`by `sqrt5` to get

`(sqrt2 - 1)/sqrt5 xx sqrt5/sqrt5 = (sqrt2 xx sqrt5 - sqrt5)/(sqrt5 xx sqrt5)`

`= (sqrt10 - sqrt5)/5`

Putting the value of `sqrt10`and `sqrt5` we get

`(sqrt10 - sqrt5)/5 = (3.162 - 2.236)/5`

`= 0.926/5`

= 0.1852

The value of expression 0.1852 can be round off tp three decimal places as 0.185.

 given expression is simplified to 0.185

  Is there an error in this question or solution?

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Solution Find the Value to Three Places of Decimals of the Following. It is Given that Sqrt2 = 1.414, Sqrt3 = 1.732, Sqrt5 = 2.236 and Sqrt10 = 3.162 Concept: Operations on Real Numbers.
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