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Find the Value to Three Places of Decimals of the Following. It is Given that Sqrt2 = 1.414, Sqrt3 = 1.732, Sqrt5 = 2.236 and Sqrt10 = 3.162 - CBSE Class 9 - Mathematics

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Question

Find the value to three places of decimals of the following. It is given that

`sqrt2 = 1.414`, `sqrt3 = 1.732`, `sqrt5 = 2.236` and `sqrt10 = 3.162`

`3/sqrt10`

Solution

 We know that rationalization factor of the denominator is `sqrt10`. We will multiply numberator and denominator of the given expression `3/sqrt10` by `sqrt10to get

`3/sqrt10 xx sqrt10/sqrt10 = (3 xx sqrt10)/(sqrt10 xx sqrt10)`

`= (3sqrt10)/10`

`= (3 xx 3.162)/10`

`= 9.486/10`

= 0.9486

The value of expression 0.9486 can be round off to three decimal places as 0.949.

Hence the given expression is simplified to 0.949.

  Is there an error in this question or solution?

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Solution Find the Value to Three Places of Decimals of the Following. It is Given that Sqrt2 = 1.414, Sqrt3 = 1.732, Sqrt5 = 2.236 and Sqrt10 = 3.162 Concept: Operations on Real Numbers.
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