# One Mole of an Ideal Gas Undergoes a Process P = P 0 1 + ( V V 0 ) 2 Where P 0 and V 0 Are Constants . Find the Temperature of the Gas When V = V 0 . - Physics

Sum

One mole of an ideal gas undergoes a process P = (P_0)/(1+(V/V_0)^2 where p_0 and V_0 are constants . Find the temperature of the gas when V=V_0 .

#### Solution

Given :

P = (p_0)/(1+(V/V_0)^2

Multiplying both sides by V, we get

pV = (p_0V)/(1+(V/V_0)^2)

pV = RT              [From eq. (1)]

Now ,

RT = (p_0V)/(1+(V/V_0)^2)

T = 1/R ((p_0V_0)/(1+(V_0/V_0)^2))       [V=V_0]

⇒ T = (p_0V_0)/(2R)

Concept: Kinetic Theory of Gases and Radiation - Kinetic Interpretation of Temperature
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#### APPEARS IN

HC Verma Class 11, Class 12 Concepts of Physics Vol. 2
Chapter 2 Kinetic Theory of Gases
Q 38 | Page 36