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One Mole of a Gas Expands by 3l Against a Constant Pressure of 3 Atmosphere. Calculate the Work Done - Chemistry

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One mole of a gas expands by 3L against a constant pressure of 3 atmosphere. Calculate the work done in -

(a) L.atmosphere

(b) Joules

(c) Calories

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Solution

Data: P = 3atm

ΔV = 3L

solution:

W = -PΔV

W = -3 x 3

W = -9L.atm

1L.atm = 101.3J

-9L.atm = -9 × 101.3J

W = -911.7J

4.184J = 1cal

∴ -911.7J = -911.7/4.184

W = -217.9cal

Concept: Chemical Thermodynamics and Energetic - Work, Heat, Energy, Extensive and Intensive Properties
  Is there an error in this question or solution?

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