When a 12 V battery is connected across an unknown resistor, there is a current of 2.5 mA in the circuit. Find the value of the resistance of the resistor.
Resistance (R) of a resistor is given by Ohm’s law as,V= IR
Potential difference, V= 12 V
Current in the circuit, I= 2.5 mA = 2.5 x 10-3 A
`R=12/(2.5xx 10^-3)=-4.8xx10^3Omega=4.8 kOmega`
Therefore, the resistance of the resistor is 4.8 kΩ
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