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Solution - Derive a Canonical Pos Expression for a Boolean Function G, Represented by the Following Truth Table: - Obtaining Sum of Product (SOP) and Product of Sum (POS) Form the Truth Table

ConceptObtaining Sum of Product (SOP) and Product of Sum (POS) Form the Truth Table

Question

Derive a Canonical POS expression for a Boolean function G, represented by the following truth table:

X Y Z G(X, Y, Z)
0 0 0 0
0 0 1 0
0 1 0 1
0 1 1 0
1 0 0 1
1 0 1 1
1 1 0 0
1 1 1 1

 

Solution

Canonical POS expression for a Boolean function G

`=(X + Y + Z)(X + Y + bar(Z))(X + bar(Y) + bar(Z))(bar(X) + bar(Y) + Z)`

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Solution for question: Derive a Canonical Pos Expression for a Boolean Function G, Represented by the Following Truth Table: concept: Obtaining Sum of Product (SOP) and Product of Sum (POS) Form the Truth Table. For the courses CBSE (Arts), CBSE (Commerce), CBSE (Science), CBSE (Science)
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