Account
It's free!

Register

Share

Books Shortlist

# Solution - Derive a Canonical Pos Expression for a Boolean Function G, Represented by the Following Truth Table: - Obtaining Sum of Product (SOP) and Product of Sum (POS) Form the Truth Table

ConceptObtaining Sum of Product (SOP) and Product of Sum (POS) Form the Truth Table

#### Question

Derive a Canonical POS expression for a Boolean function G, represented by the following truth table:

 X Y Z G(X, Y, Z) 0 0 0 0 0 0 1 0 0 1 0 1 0 1 1 0 1 0 0 1 1 0 1 1 1 1 0 0 1 1 1 1

#### Solution

Canonical POS expression for a Boolean function G

=(X + Y + Z)(X + Y + bar(Z))(X + bar(Y) + bar(Z))(bar(X) + bar(Y) + Z)

Is there an error in this question or solution?

#### Question PapersVIEW ALL [0]

Solution for question: Derive a Canonical Pos Expression for a Boolean Function G, Represented by the Following Truth Table: concept: Obtaining Sum of Product (SOP) and Product of Sum (POS) Form the Truth Table. For the courses CBSE (Arts), CBSE (Commerce), CBSE (Science), CBSE (Science)
S