Question
Derive a Canonical POS expression for a Boolean function F, represented by the following truth table
| P | Q | R | F(P,Q,R) |
| 0 | 0 | 0 | 1 |
| 0 | 0 | 1 | 0 |
| 0 | 1 | 0 | 0 |
| 0 | 1 | 1 | 1 |
| 1 | 0 | 0 | 1 |
| 1 | 0 | 1 | 0 |
| 1 | 1 | 0 | 0 |
| 1 | 1 | 1 | 1 |
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Solution
F(P,Q,R)= (P+Q+R')(P+Q'+R)(P'+Q+R')(P'+Q'+R)
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Solution for question: Derive a Canonical Pos Expression for a Boolean Function F, Represented by the Following Truth Table concept: Obtaining Sum of Product (SOP) and Product of Sum (POS) Form the Truth Table. For the courses CBSE (Arts), CBSE (Science), CBSE (Commerce), CBSE (Science)