# Obtain the differential equation by eliminating the arbitrary constants from the following equation: y = c1e2x + c2e5x - Mathematics and Statistics

Sum

Obtain the differential equation by eliminating the arbitrary constants from the following equation:

y = c1e2x + c2e5x

#### Solution

y = c1e2x + c2e5x   ....(1)

Differentiating twice w.r.t. x, we get

"dy"/"dx" = "c"_1"e"^(2"x") xx 2 + "c"_2"e"^(5"x") xx 5

∴ "dy"/"dx" = 2"c"_1"e"^(2"x") + 5"c"_2"e"^(5"x")       ....(2)

and ("d"^2"y")/"dx"^2 = 2"c"_1"e"^(2"x") xx 2 + 5"c"_2"e"^(5"x") xx 5

∴ ("d"^2"y")/"dx"^2 = 4"c"_1"e"^(2"x") + 25"c"_2"e"^("5x")      .....(3)

The equations (1), (2) and (3) are consistent in c1e2x and c2e5x

∴ determinant of their consistency is zero.

∴ |("y",1,1),("dy"/"dx",2,5),(("d"^2"y")/"dx"^2,4,25)| = 0

∴ y(50 - 20) - 1(25"dy"/"dx" - 5 ("d"^2"y")/"dx"^2) + 1 (4"dy"/"dx" - 2("d"^2"y")/"dx"^2) = 0

∴ 30y - 25"dy"/"dx" + 5("d"^2"y")/"dx"^2 + 4 "dy"/"dx" - 2("d"^2"y")/"dx"^2 = 0

∴ 3("d"^2"y")/"dx"^2 - 21"dy"/"dx" + 30"y" = 0

∴ ("d"^2"y")/"dx"^2 - 7"dy"/"dx" + 10"y" = 0

This is the required D.E.

#### Notes

[Note: Answer in the textbook is incorrect.]

Concept: Formation of Differential Equations
Is there an error in this question or solution?