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# Obtain the Potential Drop Across Each Resistor - CBSE (Science) Class 12 - Physics

ConceptCombination of Resistors – Series and Parallel

#### Question

If the combination is connected to a battery of emf 12 V and negligible internal resistance, obtain the potential drop across each resistor

#### Solution

Current flowing through the circuit = I

Emf of the battery, E = 12 V

Total resistance of the circuit, = 6 Ω

The relation for current using Ohm’s law is,

I=E/A

=12/6=2A

Potential drop across 1 Ω resistor = V1

From Ohm’s law, the value of Vcan be obtained as

V1 = 2 × 1= 2 V … (i)

Potential drop across 2 Ω resistor = V2

Again, from Ohm’s law, the value of Vcan be obtained as

V2 = 2 × 2= 4 V … (ii)

Potential drop across 3 Ω resistor = V3

Again, from Ohm’s law, the value of Vcan be obtained as

V3 = 2 × 3= 6 V … (iii)

Therefore, the potential drop across 1 Ω, 2 Ω, and 3 Ω resistors are 2 V, 4 V, and 6 V respectively.

Is there an error in this question or solution?

#### APPEARS IN

NCERT Solution for Physics Textbook for Class 12 (2018 to Current)
Chapter 3: Current Electricity
Q: 3.2 | Page no. 127

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Solution Obtain the Potential Drop Across Each Resistor Concept: Combination of Resistors – Series and Parallel.
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