Observe the ﬁgure and answer the questions.

Sachin and Sameer started on a motorbike from place A, took the turn at B, did a task at C, travelled by the route CD to D and then went on to E. Altogether, they took one hour for this journey.

Find out the actual distance traversed by them and the displacement from A to E.

From this, deduce their speed.

What was their velocity from A to E in the direction AE?

Can this velocity be called average velocity?

#### Solution

Actual distance travelled by Sachin and Sameer from A to E = AB + BC + CD + DE = 3 + 4 + 5 + 3 = 15 km

Displacement from A to E = AB + BD + DE = 3 + 3 + 3 = 9 km

`"Speed of the motorbike from A to E"`

`= "Total distance travelled from A to E"/"Total time taken from A to E" = 15/1 = 15"km/h"`

`"Velocity of the motorbike from A to E"=`

`"Total displacement from A to E"/"Total time taken from A to E" =9/1=9"km/h"`

Yes, this can be called the average velocity of the motorbike from A to E.