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O is the Center of a Circle of Radius 8cm. the Tangent at a Point a on the Circle Cuts a Line Through O at B Such that Ab = 15 Cm. Find Ob - Mathematics

Sum

O is the center of a circle of radius 8cm. The tangent at a point A on the circle cuts a line through O at B such that AB = 15 cm. Find OB

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Solution

Consider a circle with center O and radius OA = 8cm = r, AB = 15 cm.

(AB) tangent is drawn at A (point of contact)

At point of contact, we know that radius and tangent are perpendicular.

In ΔOAB, ∠OAB = 90°, By Pythagoras theorem

𝑂𝐵2 = 𝑂𝐴2 + 𝐴𝐵2

`OB = sqrt(8^2 + 15^2)`

`=sqrt(64+225)`

`= sqrt(289)`

= 17 cm

∴ 𝑂𝐵 = 17 𝑐𝑚

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APPEARS IN

RD Sharma Class 10 Maths
Chapter 8 Circles
Exercise 8.1 | Q 3 | Page 5
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