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#### Question

How many atoms constitute one unit cell of a face-centered cubic crystal?

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How can you determine the atomic mass of an unknown metal if you know its density and the dimension of its unit cell? Explain.

A unit cell of iron crystal has edge length 288 pm and density 7.86 g.cm^{-3}. Find the number of atoms per unit cell and type of the crystal lattice.

Given : Molar mass of iron = 56 g.mol^{-1}; Avogadro's number N_{A} = 6.022 x 10^{23}.

Explain how much portion of an atom located at **(i)** corner and **(ii)** body-centre of a cubic unit cell is part of its neighbouring unit cell.

An element crystallises in a b.c.c lattice with cell edge of 500 pm. The density of the element is 7.5g cm^{-3}. How many atoms are present in 300 g of the element?

Face centred cubic crystal lattice of copper has density of 8.966 g.cm^{-3}. Calculate the volume of the unit cell. Given molar mass of copper is 63.5 g mol^{-1} and Avogadro number N_{A }is 6.022 x 10^{23} mol^{-1}