#### Question

The graph of ln(R/R_{0}) versus ln A(R = radius of a nucleus and A = its mass number) is

a straight line

a parabola

an ellipse

none of them.

#### Solution

(a) a straight line

The average nuclear radius (*R*) and the mass number of the element (*A*) has the following relation :

`R = R_0A^(1/3)`

`R"/"R_0 = A^(1/3)`

In `(R"/"R_0) = 1/3 "In A"`

Therefore, the graph of ln(R/R0) versus ln A is a straight line passing through the origin with slope 1/3.

Is there an error in this question or solution?

Solution The Graph of Ln(R/R0) Versus Ln A(R = Radius of a Nucleus and a = Its Mass Number) is Concept: Nuclear Energy - Controlled Thermonuclear Fusion.