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The 17th Term of an AP Exceeds Its 10th Term by 7. Find the Common Difference. - Mathematics

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Question

The 17th term of an AP exceeds its 10th term by 7. Find the common difference.

Solution

We know that,

For an A.P., an = a + (n − 1) d

a17 = a + (17 − 1) d

a17 = a + 16d

Similarly, a10 = a + 9d

It is given that

a17 − a10 = 7

(a + 16d) − (a + 9d) = 7

7d = 7

d = 1

Therefore, the common difference is 1

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APPEARS IN

 NCERT Solution for Mathematics Textbook for Class 10 (2019 (Latest))
Chapter 5: Arithmetic Progressions
Ex. 5.2 | Q: 10 | Page no. 106
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Solution The 17th Term of an AP Exceeds Its 10th Term by 7. Find the Common Difference. Concept: nth Term of an AP.
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