#### Question

If -5 is a root of the quadratic equation 2x^{2} + px – 15 = 0 and the quadratic equation p(x^{2} + x)k = 0 has equal roots, find the value of k.

#### Solution

Given –5 is a root of the quadratic equation 2x^{2} + px – 15 = 0.

∴-5 satisfies the given equation.

∴ 2(5)^{2}+ p(-5)-15 = 0

∴ 50 - 5p - 15= 0

∴ 35-5p = 0

∴5p = 35 ⇒ p = 7

Substituting p = 7 in p(x^{2} + x)+ k= 0,we get

7(x^{2}+x)+k=0

∴7x^{2} + 7x + k = 0

The roots of the equation are equal.

∴ Discriminant b^{2} - 4ac = 0

Here, a=7, b=7, c=k

b^{2}-4ac=0

∴ (7)^{2} - 4(7)(k)=0

∴ 49-28k= 0

∴28k = 49

∴ k = `49/28=7/4`

Is there an error in this question or solution?

Solution If -5 is a root of the quadratic equation 2x^2 + px – 15 = 0 and the quadratic equation p(x^2 + x)k = 0 has equal roots, find the value of k. Concept: Nature of Roots.