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Find the Values Of K For Which the Roots Are Real and Equal in Each of the Following Equation: Kx(X - 2) + 6 = 0 - Mathematics

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Question

Find the values of k for which the roots are real and equal in each of the following equation:

kx(x - 2) + 6 = 0

Solution

The given equation is

kx(x - 2) + 6 = 0

⇒ kx2 - 2kx + 6 = 0

The given equation is in the form of ax2 + bx + c = 0

where a = k, b = -2k and c = 6

Therefore, the discriminant

D = b2 - 4ac

= (-2k)2 - 4 x (k) x (6)

= 4k2 - 24k

= 4k(k - 6)

∵ Roots of the given equation are real and equal

∴ D = 0

⇒ 4k(k - 6) = 0

⇒ k = 0

Or

⇒ k - 6 = 0

⇒ k = 6

Hence, the value of k = 0, 6.

  Is there an error in this question or solution?
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APPEARS IN

 RD Sharma Solution for Class 10 Maths (2018 (Latest))
Chapter 4: Quadratic Equations
Ex. 4.6 | Q: 5.2 | Page no. 42
 RD Sharma Solution for Class 10 Maths (2018 (Latest))
Chapter 4: Quadratic Equations
Ex. 4.6 | Q: 5.2 | Page no. 42
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Solution Find the Values Of K For Which the Roots Are Real and Equal in Each of the Following Equation: Kx(X - 2) + 6 = 0 Concept: Nature of Roots.
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