Share
Notifications

View all notifications
Advertisement

Find the Values Of K For Which the Given Quadratic Equation Has Real and Distinct Roots: Kx2 + 6x + 1 = 0 - Mathematics

Login
Create free account


      Forgot password?

Question

Find the values of k for which the given quadratic equation has real and distinct roots:

kx2 + 6x + 1 = 0

Solution

The given quadric equation is kx2 + 6x + 1 = 0, and roots are real and distinct.

Then find the value of k.

Here,

a = k, b = 6 and c = 1

As we know that D = b2 - 4ac

Putting the value of a = k, b = 6 and c = 1

D = (6)2 - 4 x (k) x (1)

= 36 - 4k

The given equation will have real and distinct roots, if D > 0

36 - 4k > 0

Now factorizing of the above equation

36 - 4k > 0

4k < 36

k < 36/4

k < 9

Now according to question, the value of k less than 9

Therefore, the value of k < 9.

  Is there an error in this question or solution?
Advertisement

APPEARS IN

 RD Sharma Solution for Class 10 Maths (2018 (Latest))
Chapter 4: Quadratic Equations
Ex. 4.6 | Q: 6.2 | Page no. 42
 RD Sharma Solution for Class 10 Maths (2018 (Latest))
Chapter 4: Quadratic Equations
Ex. 4.6 | Q: 6.2 | Page no. 42
Advertisement
Find the Values Of K For Which the Given Quadratic Equation Has Real and Distinct Roots: Kx2 + 6x + 1 = 0 Concept: Nature of Roots.
Advertisement
View in app×