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Find the Values Of K For Which the Given Quadratic Equation Has Real and Distinct Roots: Kx2 + 2x + 1 = 0 - Mathematics

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Question

Find the values of k for which the given quadratic equation has real and distinct roots:

kx2 + 2x + 1 = 0

Solution

The given quadric equation is kx2 + 2x + 1 = 0, and roots are real and distinct

Then find the value of k.

Here,

a = k, b = 2 and c = 1

As we know that D = b2 - 4ac

Putting the value of a = k, b = 2 and c = 1

D = (2)2 - 4 x (k) x (1)

= 4 - 4k

The given equation will have real and distinct roots, if D > 0

4 - 4k > 0

Now factorizing of the above equation

4 - 4k > 0

4k < 4

k < 4/4

k < 1

Now according to question, the value of k less than 1

Therefore, the value of k < 1.

  Is there an error in this question or solution?
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APPEARS IN

 RD Sharma Solution for Class 10 Maths (2018 (Latest))
Chapter 4: Quadratic Equations
Ex. 4.6 | Q: 6.1 | Page no. 42
 RD Sharma Solution for Class 10 Maths (2018 (Latest))
Chapter 4: Quadratic Equations
Ex. 4.6 | Q: 6.1 | Page no. 42
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Find the Values Of K For Which the Given Quadratic Equation Has Real and Distinct Roots: Kx2 + 2x + 1 = 0 Concept: Nature of Roots.
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