CBSE Class 10CBSE
Share
Notifications

View all notifications

Determine the Nature of the Roots of the Following Quadratic Equation: 9a2b2x2 - 24abcdx + 16c2d2 = 0 - CBSE Class 10 - Mathematics

Login
Create free account


      Forgot password?

Question

Determine the nature of the roots of the following quadratic equation:

9a2b2x2 - 24abcdx + 16c2d2 = 0

Solution

The given equation is

9a2b2x2 - 24abcdx + 16c2d2 = 0

The given equation is on the form of ax2 + bx + c = 0

where a = 9a2b2, b = -24abcd, c = 16c2d2

Therefore, the discriminant

D = b2 - 4ac

= (-24abcd)2 - 4 x (9a2b2) x (16c2d2)

= 576a2b2c2d2 - 576a2b2c2d2

= 0

∵ D = 0

∴ The roots of the given equation are real and equal.

  Is there an error in this question or solution?

APPEARS IN

Solution Determine the Nature of the Roots of the Following Quadratic Equation: 9a2b2x2 - 24abcdx + 16c2d2 = 0 Concept: Nature of Roots.
S
View in app×