CISCEICSE Class 8
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Syllabus

Multiply: 2a2 − 5a − 4 and −3a - Mathematics

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Sum

Multiply: 2a2 − 5a − 4 and −3a

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Solution

−3a (2a2 − 5a − 4)

= −3a × 2a2 − 5a × −3a − 4 × −3a

= −6a3 + 15a2 + 12a

Concept: Multiplication of Algebraic Expressions - Multiplying Monomial by Monomials
  Is there an error in this question or solution?
Chapter 11: Algebraic Expressions - Exercise 11 (C) [Page 143]
Q 1.06

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Selina Concise Mathematics Class 8 ICSE
Chapter 11 Algebraic Expressions
Exercise 11 (C) | Q 1.06 | Page 143
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