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To raise money for an orphanage, students of three schools A, B and C organised an exhibition in their locality, where they sold paper bags, scrap-books and pastel sheets made by them using recycled paper, at the rate of Rs 20, Rs 15 and Rs 5 per unit respectively. - CBSE (Science) Class 12 - Mathematics

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Question

To raise money for an orphanage, students of three schools A, B and C organised an exhibition in their locality, where they sold paper bags, scrap-books and pastel sheets made by them using recycled paper, at the rate of Rs 20, Rs 15 and Rs 5 per unit respectively. School A sold 25 paper bags, 12 scrap-books and 34 pastel sheets. School B sold 22 paper bags, 15 scrap-books and 28 pastel sheets while School C sold 26 paper bags, 18 scrap-books and 36 pastel sheets. Using matrices, find the total amount raised by each school.

By such exhibition, which values are generated in the students?

Solution

  School
Article A B C
Paper Bags 25 22 26
Scrapbooks 12 15 18
Pastel Sheets 34 28 36

The number of articles sold by each school can be written in the matrix form as follows:

`X=[[25,22,26],[12,15,18],[34,28,36]]`

The rate of each article can be written in the matrix form as follows:

Y=[20 15 5]

The amount collected by each school is given by

YX=[20 15 5]`[[25,22,26],[12,15,18],[34,28,36]]`

YX=[850 805 970]

Thus, the amount collected by schools A, B and C are Rs 850,  Rs 805 and Rs 970, respectively.

∴ Total amount collected = Rs (850 + 805 + 970)
                                         = Rs 2,625

The situation highlights the helpful nature of the students.

  Is there an error in this question or solution?

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Solution To raise money for an orphanage, students of three schools A, B and C organised an exhibition in their locality, where they sold paper bags, scrap-books and pastel sheets made by them using recycled paper, at the rate of Rs 20, Rs 15 and Rs 5 per unit respectively. Concept: Multiplication of Two Matrices.
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