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Sum

Mr. Manish purchased a motorcycle at Rs.70,000/-. After some years he sold his motorcycle at the exact depreciated value of it that is Rs.51,030/-. The rate of depreciation was taken as 10%. Find after how many years he sold his motorcycle.

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#### Solution

Given, purchase price of the motorcycle = V

= ₹ 70,000/-

Depreciated value of the motorcycle = D.V. = ₹ 51,030/-

∴ Rate of depreciation = r = 10%

Using, D.V. = V`(1 - "r"/100)^"n"`

∴ 51,030 = 70,000`(1 - 10/100)^"n"`

∴ `(1 - 1/10)^"n" = (51,030)/(70,000)`

∴ `(9/10)^"n" = 729/1000 = (9/10)^3`

∴ n = 3

∴ Manish sold his motorcycle after 3 years.

Concept: Depreciation

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