#### Question

The combined resistance of a galvanometer of resistance 500Ω and its shunt is 21Ω. Calculate the value of shunt.

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#### Solution

Here, G = 500Ω and Req = 21Ω

`1/R_(eq)=1/G+1/S`

`therefore 1/S=1/R_(eq)-1/G=(G-R_(eq))/(GxxR_(eq)`

`therefore S=(GxxR_(eq))/(G-R_(eq)`

`therefore S=(500xx21)/(500-21)=10500/479`

`therefore S= 21.92 Omega`

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Solution for question: The Combined Resistance of a Galvanometer of Resistance 500Ω and Its Shunt is 21Ω. Calculate the Value of Shunt concept: Moving Coil Galvanometer. For the courses HSC Science (Computer Science), HSC Science (Electronics), HSC Science (General)