#### Question

The combined resistance of a galvanometer of resistance 500Ω and its shunt is 21Ω. Calculate the value of shunt.

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#### Solution

Given:

G = 500Ω

R_{eq} = 21Ω

To Find:

S = ?

Formula:

1/R_{eq} = 1/G + 1/S

Solution:

1/R_{eq} = 1/G + 1/S

1/S = 1/R_{eq} - 1/G = (G - R_{eq})/R_{eq}G

∴ S = R_{eq}G/(G - R_{eq})

∴ S = 21 × 500/(500 - 21)

∴ S = 10500/479

∴ S = 21.92Ω

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#### Reference Material

Solution for question: Calculate the Value of Shunt. concept: Moving Coil Galvanometer. For the courses HSC Science (Electronics), HSC Science (Computer Science), HSC Science (General)