Sum

Mosquitoes are growing at a rate of 10% a year. If there were 200 mosquitoes in the beginning. Write down the number of mosquitoes after 10 years.

Advertisement Remove all ads

#### Solution

Since mosquitoes are growing at a rate of 10% and there were 200 mosquitoes, in the beginning, the number of mosquitoes in successive years form a G.P. with a = 200 and r = `1+10/100=11/10`

Number of mosquitoes after 10 years

= t_{11}

= ar^{11–1}

= `200(11/10)^10`

= 200 (1.1)^{10}

Concept: Geometric Progression (G. P.)

Is there an error in this question or solution?

Advertisement Remove all ads

#### APPEARS IN

Advertisement Remove all ads

Advertisement Remove all ads