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# Solution - Using Cofactors of Elements of Third Column, Evaluate Triangle = |(1,X,Yz),(1,Y,Zx),(1,Z,Xy)| - Minors and Co-factors

ConceptMinors and Co-factors

#### Question

Using Cofactors of elements of third column, evaluate triangle = |(1,x,yz),(1,y,zx),(1,z,xy)|

#### Solution

The given determinant is  |(1,x,yz),(1,y,zx),(1,z,xy)|

We have:

∴A13 = cofactor of a13 = (−1)1+3 M13 = (z − y)

A23 = cofactor of a23 = (−1)2+3 M23 = − (z − x) = (x − z)

A33 = cofactor of a33 = (−1)3+3 M33 = (y − x)

We know that Δ is equal to the sum of the product of the elements of the second row with their corresponding cofactors.

Is there an error in this question or solution?

#### APPEARS IN

NCERT Mathematics Textbook for Class 12 Part 1
Chapter 4: Determinants
Q: 4 | Page no. 126

#### Reference Material

Solution for question: Using Cofactors of Elements of Third Column, Evaluate Triangle = |(1,X,Yz),(1,Y,Zx),(1,Z,Xy)| concept: Minors and Co-factors. For the courses CBSE (Arts), CBSE (Commerce), CBSE (Science)
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