HSC Science (Electronics) 12th Board ExamMaharashtra State Board
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Solution - When a Resistance of 12 Ohm is Connected Across a Cell, Its Terminal Potential Difference Is Balanced by 120 Cm Length of Potentiometer Wire. - HSC Science (Electronics) 12th Board Exam - Physics

Question

When a resistance of 12 ohm is connected across a cell, its terminal potential difference is balanced by 120 cm length of potentiometer wire. When the resistance of 18 ohm is connected across the same cell, the balancing length is 150 cm. Find the balancing length when the cell is in open circuit. Also calculate the internal resistance of the cell.

Solution

Solution:
Given:

R1 = 12Ω, l2 = 120 cm,
R2= 18 Ω,` l_2^'` = 150 cm

To find:

Balancing length (l1),
Internal resistance (r)

Solution:

`r=R((l_1-l_2)/l_2)`

`r=12((l_1-120)/120)`.......................(1)

From second condition

`r=18((l_1-150)/150)`......................(2)

 

From equation 1 and 2 

`12((l_1-120)/120)=18((l_1-150)/150)`

`5(l_1-120)=6(l_1-150)`

`l_1=300 cm`

Using equation (i) we get Internal resistance,

`r=R((l_1-l_2)/l_2)`

`r=12((300-120)/120)`

`r=18Omega`

i. The balancing length is 300 cm.
ii. The internal resistance of the cell is 18 Ω.

Is there an error in this question or solution?

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Reference Material

Solution for question: When a Resistance of 12 Ohm is Connected Across a Cell, Its Terminal Potential Difference Is Balanced by 120 Cm Length of Potentiometer Wire. concept: null - Metre Bridge. For the courses HSC Science (Electronics), HSC Science (General) , HSC Science (Computer Science)
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