#### Question

In potentiometer experiment, if l_{1} is the balancing length for e.m.f. of cell of internal resistance r and l_{2} is the balancing length for its terminal potential difference when shunted with resistance R then :

(a) `l_1=l_2((R+r)/R)`

(b) `l_1=l_2((R)/(R+r))`

(c) `l_1=l_2((R)/(R-r))`

(d) `l_1=l_2((R-r)/R)`

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#### Solution

(a)`l_1=l_2((R+r)/R)`

The internal resistance of a cell is given as

`r= ((l_1-l_2)/l_2)R`

→`r/R=(l_1-l_2)/l_2`

∴ `rl_2=Rl_1-Rl_2`

∴`l_2(R+r)=Rl_1`

∴`l_1=l_2(R+r)/R`

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#### APPEARS IN

Solution for question: What is the Balancing Length for Its Terminal Potential Difference When Shunted with Resistance R concept: Metre Bridge. For the courses HSC Science (Electronics), HSC Science (Computer Science), HSC Science (General)