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# Solution - What is the Balancing Length for Its Terminal Potential Difference When Shunted with Resistance R - Metre Bridge

#### Question

In potentiometer experiment, if l1 is the balancing length for e.m.f. of cell of internal resistance r and l2 is the balancing length for its terminal potential difference when shunted with resistance R then :

(a) l_1=l_2((R+r)/R)

(b) l_1=l_2((R)/(R+r))

(c) l_1=l_2((R)/(R-r))

(d) l_1=l_2((R-r)/R)

#### Solution

(a)l_1=l_2((R+r)/R)

The internal resistance of a cell is given as

r= ((l_1-l_2)/l_2)R

→r/R=(l_1-l_2)/l_2

∴ rl_2=Rl_1-Rl_2

∴l_2(R+r)=Rl_1

∴l_1=l_2(R+r)/R

Is there an error in this question or solution?

#### APPEARS IN

2015-2016 (March)
Question 6.4 | 1 mark

#### Video TutorialsVIEW ALL [3]

Solution for question: What is the Balancing Length for Its Terminal Potential Difference When Shunted with Resistance R concept: Metre Bridge. For the courses HSC Science (Computer Science), HSC Science (Electronics), HSC Science (General)
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