#### Question

Find the particular solution of the differential equation:

`y(1+logx) dx/dy - xlogx = 0`

when y = e^{2} and x = e

#### Solution

Given equation is

`y(1 + logx) dx/dy -xlogx = 0`

`:. y(1+logx) dx/dy = xlogx`

`:. y(1+logx)dx = xlogx dy`

Separating the variables

`1/ydy = (1+logx)/(xlogx) dx`

Integrating, we have

`int1/y dy = int (1+logx)/(xlogx) dx`

`:.log|y| = log|xlogx|+logc`

`:. log|y| = log|cxlogx|`

∴ y = cx log x is the general solution

Given x = e, y = e^{2}

∴ e^{2} = c.e.log e

∴ `e^2 = c.e`

∴ c = e

∴y = ex.logx

Is there an error in this question or solution?

#### APPEARS IN

Solution Find the Particular Solution of the Differential Equation: Y ( 1 + Log X ) D X D Y − X Log X = 0 When Y = E2 and X = E Concept: Methods of Solving First Order, First Degree Differential Equations - Differential Equations with Variables Separable.