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# The treatment of alkyl chlorides with aqueous KOH leads to the formation of alcohols but in the presence of alcoholic KOH, alkenes are major products. Explain. - CBSE (Science) Class 12 - Chemistry

ConceptMethods of Preparation of Haloalkanes and Haloarenes

#### Question

The treatment of alkyl chlorides with aqueous KOH leads to the formation of alcohols but in the presence of alcoholic KOH, alkenes are major products. Explain.

#### Solution 1

In an aqueous solution, KOH almost completely ionizes to give OH ions. OH ion is a strong nucleophile, which leads the alkyl chloride to undergo a substitution reaction to form alcohol.

R - Cl       +         KOH_(aq) -> R - OH + KCl

Alkyl chloride                           Alcohol

On the other hand, an alcoholic solution of KOH contains alkoxide (RO) ion, which is a strong base. Thus, it can abstract a hydrogen from the β-carbon of the alkyl chloride and form an alkene by eliminating a molecule of HCl.

OH ion is a much weaker base than RO ion. Also, OH ion is highly solvated in an aqueous solution and as a result, the basic character of OH ion decreases. Therefore, it cannot abstract a hydrogen from the β-carbon.

#### Solution 2

If aqueous solution, KOH is almost completely ionized to give OH ions which being a strong nucleophile brings about a substitution reaction on alkyl halides to form alcohols. Further in the aqueous solution, OH ions are highly solvated (hydrated). This solvation reduces the basic character of OH ions which, therefore, fails to abstract a hydrogen from the P-carbon of the alkyl chloride to form alkenes. In contrast, an alcoholic solution of KOH contains alkoxide (RO) ion which being a much stronger base than OH ions perferentially eliminates a molecule of HCl from an alkyl chloride to form alkenes.

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#### APPEARS IN

NCERT Solution for Chemistry Textbook for Class 12 (2018 to Current)
Chapter 10: Haloalkanes and Haloarenes
Q: 20 | Page no. 312

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Solution The treatment of alkyl chlorides with aqueous KOH leads to the formation of alcohols but in the presence of alcoholic KOH, alkenes are major products. Explain. Concept: Methods of Preparation of Haloalkanes and Haloarenes.
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