#### Question

Evaluate : `∫(x+1)/((x+2)(x+3))dx`

#### Solution

Let I=`∫(x+1)/((x+2)(x+3))dx`

`(x+1)/((x+2)(x+3))=A/(x+2)+B/(x+3)`

`x+1=A(x+3)+B(x+2)` .........(i)

∴ Putting x = -2 in equation (i) we get

-1 = A

∴ A = -1

∴ Putting x = -3 in equation (i) we get

-2 = -B

∴ B = 2

∴(x+1)/((x+2)(x+3))=1/(x+2)+2/(x+3)

`∴ I=int[-1/(x+2)+2/(x+3)]dx`

`∴I=-log|x+2|+2log|x+3|+c`

Is there an error in this question or solution?

#### APPEARS IN

Solution for question: Evaluate : ∫(x+1)/((x+2)(x+3))dx concept: Methods of Integration - Integration Using Partial Fractions. For the courses HSC Arts, HSC Science (Electronics), HSC Science (General) , HSC Science (Computer Science)