#### Question

100 surnames were randomly picked up from a local telephone directory and the frequency distribution of the number of letters in the English alphabets in the surnames was obtained as follows:

Number of letters |
Number of surnames |

1 - 4 | 6 |

4 − 7 | 30 |

7 - 10 | 40 |

10 - 13 | 6 |

13 - 16 | 4 |

16 − 19 | 4 |

Determine the median number of letters in the surnames. Find the mean number of letters in the surnames? Also, find the modal size of the surnames.

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#### Related Questions VIEW ALL [3]

The median of the following data is 525. Find the missing frequency, if it is given that there are 100 observations in the data:

Class interval | Frequency |

0 - 100 | 2 |

100 - 200 | 5 |

200 - 300 | f1 |

300 - 400 | 12 |

400 - 500 | 17 |

500 - 600 | 20 |

600 - 700 | f2 |

700 - 800 | 9 |

800 - 900 | 7 |

900 - 1000 | 4 |

The following table gives the frequency distribution of married women by age at marriage:

Age (in years) | Frequency |

15-19 | 53 |

20-24 | 140 |

25-29 | 98 |

30-34 | 32 |

35-39 | 12 |

40-44 | 9 |

45-49 | 5 |

50-54 | 3 |

55-59 | 3 |

60 and above | 2 |

Calculate the median and interpret the results.

An incomplete distribution is given below:

Variable: | 10-20 | 20-30 | 30-40 | 40-50 | 50-60 | 60-70 | 70-80 |

Frequency: | 12 | 30 | - | 65 | - | 25 | 18 |

You are given that the median value is 46 and the total number of items is 230.

(i) Using the median formula fill up missing frequencies.

(ii) Calculate the AM of the completed distribution.