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# In a mathematics test given to 15 students, the following marks (out of 100) are recorded:- 41, 39, 48, 52, 46, 62, 54, 40, 96, 52, 98, 40, 42, 52, 60 Find the mean, median and mode of this data. - CBSE Class 9 - Mathematics

ConceptMeasures of Central Tendency

#### Question

In a mathematics test given to 15 students, the following marks (out of 100) are recorded:-

41, 39, 48, 52, 46, 62, 54, 40, 96, 52, 98, 40, 42, 52, 60

Find the mean, median and mode of this data.

#### Solution

The marks of 15 students in mathematics test are

41, 39, 48, 52, 46, 62, 54, 40, 96, 52, 98, 40, 42, 52, 60

"Mean of data "="Sum of all observation"/"Total number of observations"

= (41+39+48+52+46+62+54+40+96+52+98+40+42+52+60)/15

= 822/15 = 54.8

Arranging the scores obtained by 15 students in an ascending order,

39, 40, 40, 41, 42, 46, 48, 52, 52, 52, 54, 60, 62, 96, 98

As the number of observations is 15 which is odd, therefore, the median of data will be (15 + 1)/2= 8thobservation whether the data is arranged in an ascending or descending order.

Therefore, median score of data = 52

Mode of data is the observation with the maximum frequency in data. Therefore, mode of this data is 52 having the highest frequency in data as 3.

Is there an error in this question or solution?

#### APPEARS IN

NCERT Solution for Mathematics Class 9 (2018 to Current)
Chapter 14: Statistics
Ex. 14.40 | Q: 2 | Page no. 269

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Solution In a mathematics test given to 15 students, the following marks (out of 100) are recorded:- 41, 39, 48, 52, 46, 62, 54, 40, 96, 52, 98, 40, 42, 52, 60 Find the mean, median and mode of this data. Concept: Measures of Central Tendency.
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